Date: Tue, 08 Sep 2009 08:00:27 +0200 From: Mark Stapper <stark@mapper.nl> To: Gary Kline <kline@thought.org> Cc: FreeBSD Mailing List <freebsd-questions@FreeBSD.ORG> Subject: Re: how to get rid of a character, 0x80? Message-ID: <4AA5F2FB.8080006@mapper.nl> In-Reply-To: <20090908045202.GA16556@thought.org>
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[-- Attachment #1 --] Gary Kline wrote: > anybody know why getchar() doesn't see 0x80 == 0200? if getchar() > is limited to 7-bit characters, what then? > > % od -c file > > shows me that every character fits into 8 bits, so getwchar() is the next thing. > but doesn't getwchar grab wide-chars only: 16 bits? > > tia, guys, > > gary > > > > Hello, First of, this isn't really a BSD question. Second, if you have an example code we might be able to help. Presumably, you want to read a capital C with cedille? (0x80 128 Ç) Example from: http://www.cplusplus.com/reference/clibrary/cstdio/getchar/ compiled on FreeBSD 7.2 with gcc 4.2.1 output: " Enter text. Include a dot ('.') in a sentence to exit: sfeo sfeo Çsdfa Çsdfa " besides.. 0x80!=0200 it's 0200 octal which is 128 decimal... Might be why it doesn't work for you. Greetz, Mark [-- Attachment #2 --] -----BEGIN PGP SIGNATURE----- Version: GnuPG v1.4.9 (MingW32) Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/ iEYEARECAAYFAkql8v0ACgkQN9xNqOOVnWBUFgCfZJz2JbaWsrpJhSa6vZ4SeNjm v00AoIIHVdzWb2PHDb26KDq2dQ22wLMd =D+QA -----END PGP SIGNATURE-----home | help
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