Date: Wed, 05 May 2010 21:34:23 -0500 From: CyberLeo Kitsana <cyberleo@cyberleo.net> To: Evuraan <evuraan@gmail.com> Cc: Paul Hoffman <phoffman@proper.com>, freebsd-questions@freebsd.org Subject: Re: bash while read question Message-ID: <4BE22AAF.8020608@cyberleo.net> In-Reply-To: <x2n6fbcd0711005051825mf0835e29jbf5daaab5111b336@mail.gmail.com> References: <x2n6fbcd0711005051825mf0835e29jbf5daaab5111b336@mail.gmail.com>
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On 05/05/2010 08:25 PM, Evuraan wrote: > I cant figure out why the variable in in loop2 does not hike to +1? > (its a friday, i am dazed, I admit. but this should not be a mystery!) > any help would be much appreciated. > <snip> > $ cat loop2 > #! /bin/bash > > date > /tmp/somefile > b="1" > cat /tmp/somefile | while read blah; do > let b=(b+1) > done > echo "variable is $b" This particular syntax executes the 'while' block in a subshell. The variables set or altered in the subshell are never propagated back up to the parent shell. -- Fuzzy love, -CyberLeo Technical Administrator CyberLeo.Net Webhosting http://www.CyberLeo.Net <CyberLeo@CyberLeo.Net> Furry Peace! - http://wwww.fur.com/peace/
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