Date: Sun, 06 Jun 2010 12:57:37 +0800 From: Aiza <aiza21@comclark.com> To: CyberLeo Kitsana <cyberleo@cyberleo.net> Cc: "questions@freebsd.org" <questions@freebsd.org>, Dan Nelson <dnelson@allantgroup.com> Subject: Re: .sh & getopts Message-ID: <4C0B2AC1.1080805@comclark.com> In-Reply-To: <4C0B26B5.3090901@cyberleo.net> References: <201006051513.o55FDCKj020952@mail.r-bonomi.com> <4C0ADBCF.8040506@comclark.com> <AANLkTimDVOQE-SrT7YO4UD3tktD81jy8px6dbbB83-Dl@mail.gmail.com> <20100606014737.GG85961@dan.emsphone.com> <4C0B1C61.9030501@comclark.com> <4C0B26B5.3090901@cyberleo.net>
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CyberLeo Kitsana wrote: > On 06/05/2010 10:56 PM, Aiza wrote: >> i) action="installworld"; $flag_count=$((flag_count+1));; >> ... >> What is still wrong here > > Bourne shell expands variables to their contents before evaluating. > Thus, the above assignment ends up expanding to '0=1'. Leave out the $ > on the target variable, and it becomes 'flag_count=1', which is more > likely what you intended. > i) action="installworld"; flag_count=$((flag_count+1));; But when tested it just put 1 into flag_count. it is not adding one to the value all ready in flag_count. Stilling missing the point here I want to perform math here. if more than one flag is coded them I want the count to increase by 1 for each flag on the command, not change the contents of the count to 1. Again take note this is .sh shell type.home | help
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