Date: Tue, 06 Mar 2007 07:27:56 -0600 From: Derek Ragona <derek@computinginnovations.com> To: Gary Kline <kline@tao.thought.org>, FreeBSD Mailing List <freebsd-questions@freebsd.org> Subject: Re: awk question Message-ID: <6.0.0.22.2.20070306072709.02577448@mail.computinginnovations.com> In-Reply-To: <20070306003506.GA12553@thought.org>
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You can loop through them using a shell script:
for i in `ls -lt | awk '{if ($8 == 2006) print $9}'`;do rm $i;done
-Derek
At 06:35 PM 3/5/2007, Gary Kline wrote:
> Guys,
>
> Having found $9 , how do I /bin/rm it (using system()--yes??)
> in an awk one-liner?
>
> I'm trying to remove from packages from long ago and find and
> print them with
>
> ls -lt | awk '{if ($8 == 2006) print $9}';
>
> but what I want to remove the file pointed at by $9. I've tried
> FILE=ARGV[9]; and using FILE within my system() call, but no-joy.
> What's the magic here?
>
> thanks in advance,
>
> gary
>
>
>
>--
> Gary Kline kline@thought.org www.thought.org Public Service Unix
>
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