Date: Tue, 06 Mar 2007 09:29:55 -0600 From: Scott Oertel <freebsd@scottevil.com> To: Gary Kline <kline@tao.thought.org> Cc: FreeBSD Mailing List <freebsd-questions@freebsd.org> Subject: Re: awk question Message-ID: <45ED88F3.8040200@scottevil.com> In-Reply-To: <20070306003506.GA12553@thought.org> References: <20070306003506.GA12553@thought.org>
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Gary Kline wrote:
> Guys,
>
> Having found $9 , how do I /bin/rm it (using system()--yes??)
> in an awk one-liner?
>
> I'm trying to remove from packages from long ago and find and
> print them with
>
> ls -lt | awk '{if ($8 == 2006) print $9}';
>
> but what I want to remove the file pointed at by $9. I've tried
> FILE=ARGV[9]; and using FILE within my system() call, but no-joy.
> What's the magic here?
>
> thanks in advance,
>
> gary
>
>
>
>
Another way is:
ls -lt | awk '{if ($8 == 2006) print "rm -rf "$9}' | sh
but I agree, using pkg_delete would be safer:
ls -lt | awk '{if ($8 == 2006) print "pkg_delete "$9}' | sh
-SO
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